Code will a lot simple without additional encoding/decoding. I don't know why you so afraid of using byte type and why you need everything be BASE64 encoded. I'll suggest to throw RSACrypto class, or rewrite it at least. Just remove new keypair generation from encrypt, call newKeyPair direcly, when you need it.Īnd that static variables does no good for multi-thread environment. When you encrypt file, it creates every time new keypair (in encrypt). How do I pass the private key from file/simple string so that the key is not modified. (crypt(this.encryptedText, sb.toString())) Īll the encryption/decryption string will return in Base64Encoder/Base64Decoder format. This.encryptedText = RSACrypto.encrypt('PLAIN TEXT', sb.toString())

Then I am using below code to decrypt the data File privfile = new File('C:\temp-ldi\privkey.txt') įile pubfile = new File('C:\temp-ldi\pubkey.txt') įileReader reader = new FileReader(pubfile) īufferedReader br = new BufferedReader(reader) Writer.write(new BASE64Encoder().encode(RSACrypto.privKeyToBytes(RSACrypto.privateKey))) Writer.write(new BASE64Encoder().encode(RSACrypto.pubKeyToBytes(RSACrypto.publicKey))) įile = new File('C:\temp-ldi\privkey.txt') We have one public key and private key and will be using same throughout.īut the problem is, when I decrypt, I am getting : Data must start with zero File file = new File('C:\temp-ldi\pubkey.txt') įileWriter writer = new FileWriter(file) ĮncryptedText = RSACrypto.encrypt('PLAIN TEXT') //no argument of pub-key, generate key pair I am trying to encrypt and decrypt the data with RSA 2048.

Decrypt rsa 2048 python